James Holzhauer - who made headlines this year for his run on "Jeopardy!" - is returning for a special "Greatest of All Time" tournament ... and he's using "Steiner Math" to hype it up. The first one to win three of these games will receive $1 million and the bragging rights of "Jeopardy!". Rutter started playing the game in 2000 when rules dictated that after five consecutive wins a player must retire, but was guaranteed a spot in the "Tournament of Champions", which he won.
Fans have been clamoring to see Holzhauer, the 35-year-old gambler from Las Vegas who won an additional $250,00 in the Tournament of Champions Friday, take on the game show's most storied competitors.
The best "Jeopardy!" players in history will compete against each other for the first time ever.
"We're excited to bring 'Jeopardy!' to prime time".
Jennings earned Jeopardy! fame in 2004 with his 74-game winning streak, the longest in the show's history (which amassed $3,370,700). The victor will receive $1 million while the two other players will received $250,000.
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"Based on their previous performances, these three are already the 'greatest, ' but you can't help wondering: who is the best of the best?"
"Jeopardy! The Greatest of All Time" is being produced by Sony Pictures Television with Harry Friedman serving as executive producer.
In a statement, Trebek said the three have proved they qualify as the "greatest", and now will compete to be "the best of the best". Rutter, meanwhile, is the highest money victor across any TV game show, with total winnings of $4,688,436.
The Greatest of All time event will air as follows: Tuesday, Jan. 7 (8-9 p.m. ET), Wednesday, Jan. 8 (8-9 p.m. ET) and Thursday, Jan. 9 (8-9 p.m. ET).